Calculus-Based Physics by Jeffrey W. Schnick - HTML preview

Chapter 23 Statics

Here, I copy that last line for you before proceeding:

− x mg + xF = 0

2

N

g

m

F =

N

2

6.

kg

92

(9

.

)

newtons/kg

80

F =

N

2

F = 32 .

newtons

9

N

g

m

We can use this result ( F =

) in equation 23-6 (the one that reads F − mg + F = 0 ) to

N

2

P y

N

obtain a value for F :

Py

F − mg + F = 0

P y

N

F

= mg − F

P y

N

g

m

F

= m −

Py

g

2

g

m

F

=

Py

2

6.

(9

kg

92

.

)

newtons/kg

80

F

=

P y

2

F

= 32. newtons

9

P y

Recalling that we found F to be zero, we can write, for our final answer:

Px

F = 32.9 newtons, straight upward

P

and

F = 32.9 newtons, straight upward

N

1

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