Algebra Foundations for Normal People by Gabriel Beguerie - HTML preview
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Chapter 12
Worked example (no skipped steps)
12.1 Use π΄ = ππ€ with π = 8 and π€ = 3.
Substitute the values:
π΄ = (8)(3)
Multiply:
π΄ = 24
Answer: 24.
Worked example (no skipped steps)
12.2 Use π = ππ‘ with π = 60 and π‘ = 2 . 5.
Substitute:
π = (60)(2 . 5)
Multiply:
π = 150
Answer: 150.
Worked example (no skipped steps)
12.3 Use π¦ = ππ₯ + π with π = 2, π₯ = 5, π = β3.
Substitute carefully:
π¦ = (2)(5) + (β3)
Now simplify:
π¦ = 10 β 3 = 7
Answer: 7.
Step-by-step solutions
Worked example (no skipped steps)
12.4 Solve for π in π¦ = ππ₯ + π.
Subtract ππ₯ from both sides:
π¦ β ππ₯ = π
So:
π = π¦ β ππ₯
Answer: π = π¦ β ππ₯.
Worked example (no skipped steps)
12.5 Solve for π‘ in π = ππ‘.
Divide both sides by π:
π
ππ‘
=
π
π
So:
π
π‘ = π
Answer: π‘ = π (with π ΜΈ= 0).
π
Worked example (no skipped steps)
12.6 Solve for π€ in π = 2 π + 2 π€.
Subtract 2 π from both sides:
π β 2 π = 2 π€
Now divide by 2:
π β 2 π
π€ =
2
Answer: π€ = π β2 π .
2
Worked example (no skipped steps)
12.7 Solve for πΆ in πΉ = 9 πΆ + 32.
5
Subtract 32:
9
πΉ β 32 =
πΆ
5
Multiply both sides by the reciprocal 5 :
9
5 ( πΉ β 32) = πΆ
9
So:
5
πΆ =
( πΉ β 32)
9
Answer: πΆ = 5 ( πΉ β 32).
9
185
Worked example (no skipped steps)
12.8 Solve for π in π΄ = ππ 2.
Divide by π:
π΄ = π 2
π
Take the square root of both sides:
βοΈ
π΄
π =
π
βοΈ
Answer: π =
π΄ .
π
Worked example (no skipped steps)
12.9 Solve for π₯ in π₯β π = π.
π
Multiply both sides by π:
π₯ β π = ππ
Add π to both sides:
π₯ = ππ + π
Answer: π₯ = ππ + π.
Worked example (no skipped steps)
12.10 Solve for π in π΄ = 1 πβ.
2
Multiply both sides by 2:
2 π΄ = πβ
Now divide by β:
2 π΄
π = β
Answer: π = 2 π΄ (with β ΜΈ= 0).
β
Worked example (no skipped steps)
12.11 Solve for π₯ in π§ = π₯β π¦ .
3
Multiply both sides by 3:
3 π§ = π₯ β π¦
Add π¦ to both sides:
π₯ = 3 π§ + π¦
Answer: π₯ = 3 π§ + π¦.
Step-by-step solutions
Worked example (no skipped steps)
12.12 Use π = 2 π + 2 π€ with π = 7 and π€ = 4.
Substitute:
π = 2(7) + 2(4)
Simplify:
π = 14 + 8 = 22
Answer: 22.
Worked example (no skipped steps)
12.13 Use πΌ = π ππ‘ with π = 500, π = 0 . 08, π‘ = 2.
Substitute:
πΌ = (500)(0 . 08)(2)
Multiply step by step:
500 Β· 0 . 08 = 40
40 Β· 2 = 80
Answer: 80.
Worked example (no skipped steps)
12.14 Solve for π in πΌ = π ππ‘.
Divide both sides by ππ‘:
πΌ
π = ππ‘
Answer: π = πΌ (with π ΜΈ= 0 and π‘ ΜΈ= 0).
ππ‘
Worked example (no skipped steps)
12.15 Solve for β in π΄ = 1 πβ.
2
Multiply both sides by 2:
2 π΄ = πβ
Divide both sides by π:
2 π΄
β = π
Answer: β = 2 π΄ (with π ΜΈ= 0).
π
187
Worked example (no skipped steps)
12.16 Solve for π₯ in π¦ = ππ₯ + π.
Subtract π:
π¦ β π = ππ₯
Divide by π:
π¦ β π
π₯ =
π
Answer: π₯ = π¦β π (with π ΜΈ= 0).
π
Worked example (no skipped steps)
12.17 Solve for π in πΆ = 2 ππ.
Divide both sides by 2 π:
πΆ
π = 2 π
Answer: π = πΆ .
2 π
Worked example (no skipped steps)
12.18 Use πΆ = 2 ππ with π = 3.
Substitute:
πΆ = 2 π(3)
Simplify:
πΆ = 6 π
Answer: 6 π.
Worked example (no skipped steps)
12.19 Use π = π’π‘ + 1 ππ‘ 2 with π’ = 4, π = 2, π‘ = 3.
2
Substitute:
1
π = (4)(3) +
(2)(32)
2
Simplify each part:
(4)(3) = 12
32 = 9
1 (2)(9) = 1 Β· 9 = 9
2
Now add:
π = 12 + 9 = 21
Answer: 21.
Step-by-step solutions
Worked example (no skipped steps)
12.20 Solve for π in π = π’π‘ + 1 ππ‘ 2.
2
Subtract π’π‘ from both sides:
1
π β π’π‘ =
ππ‘ 2
2
Multiply both sides by 2:
2( π β π’π‘) = ππ‘ 2
Now divide by π‘ 2:
2( π β π’π‘)
π =
π‘ 2
Answer: π = 2( π β π’π‘) (with π‘ ΜΈ= 0).
π‘ 2
