Algebra Foundations for Normal People by Gabriel Beguerie - HTML preview
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Chapter 7
Worked example (no skipped steps)
7.1 Solve 3( ๐ฅ + 2) = 18.
Distribute:
3 ๐ฅ + 6 = 18
Subtract 6:
3 ๐ฅ = 12
Divide by 3:
๐ฅ = 4
Step-by-step solutions
Worked example (no skipped steps)
7.2 Solve 4(2 ๐ฆ โ 1) = 20.
Distribute:
8 ๐ฆ โ 4 = 20
Add 4:
8 ๐ฆ = 24
Divide by 8:
๐ฆ = 3
Worked example (no skipped steps)
7.3 Solve 5 โ 2( ๐ฅ + 1) = โ9.
Distribute:
5 โ 2 ๐ฅ โ 2 = โ9
Combine like terms:
3 โ 2 ๐ฅ = โ9
Subtract 3:
โ2 ๐ฅ = โ12
Divide by โ2:
๐ฅ = 6
Worked example (no skipped steps)
7.4 Solve 2( ๐ฅ โ 3) + 4 = 10.
Distribute:
2 ๐ฅ โ 6 + 4 = 10
Combine:
2 ๐ฅ โ 2 = 10
Add 2:
2 ๐ฅ = 12
Divide by 2:
๐ฅ = 6
161
Worked example (no skipped steps)
7.5 Solve 5 ๐ฅ โ 7 = 2 ๐ฅ + 8.
Subtract 2 ๐ฅ:
3 ๐ฅ โ 7 = 8
Add 7:
3 ๐ฅ = 15
Divide by 3:
๐ฅ = 5
Worked example (no skipped steps)
7.6 Solve 6 ๐ + 3 = 2 ๐ + 15.
Subtract 2 ๐:
4 ๐ + 3 = 15
Subtract 3:
4 ๐ = 12
Divide by 4:
๐ = 3
Worked example (no skipped steps)
7.7 Solve 3 ๐ฅ + 4 = 2 ๐ฅ + 11.
Subtract 2 ๐ฅ:
๐ฅ + 4 = 11
Subtract 4:
๐ฅ = 7
Worked example (no skipped steps)
7.8 Solve 4( ๐ฅ โ 1) + 3 = 2 ๐ฅ + 9.
Distribute:
4 ๐ฅ โ 4 + 3 = 2 ๐ฅ + 9
Combine:
4 ๐ฅ โ 1 = 2 ๐ฅ + 9
Subtract 2 ๐ฅ:
2 ๐ฅ โ 1 = 9
Add 1:
2 ๐ฅ = 10
Divide by 2:
๐ฅ = 5
Step-by-step solutions
Worked example (no skipped steps)
7.9 Solve 2( ๐ฅ + 3) โ 4 = ๐ฅ + 9.
Distribute:
2 ๐ฅ + 6 โ 4 = ๐ฅ + 9
Combine:
2 ๐ฅ + 2 = ๐ฅ + 9
Subtract ๐ฅ:
๐ฅ + 2 = 9
Subtract 2:
๐ฅ = 7
Worked example (no skipped steps)
7.10 Solve 3 โ (2 ๐ฅ โ 5) = 12.
Distribute the negative sign:
3 โ 2 ๐ฅ + 5 = 12
Combine:
8 โ 2 ๐ฅ = 12
Subtract 8:
โ2 ๐ฅ = 4
Divide by โ2:
๐ฅ = โ2
Worked example (no skipped steps)
7.11 Solve ๐ฅ + ๐ฅ = 5.
2
3
Multiply every term by 6:
๐ฅ
๐ฅ
6 ยท
+ 6 ยท
= 6 ยท 5
2
3
Simplify:
3 ๐ฅ + 2 ๐ฅ = 30
So:
5 ๐ฅ = 30
Divide by 5:
๐ฅ = 6
163
Worked example (no skipped steps)
7.12 Solve ๐ฅ + 5 = 9.
3
Subtract 5:
๐ฅ = 4
3
Multiply by 3:
๐ฅ = 12
Worked example (no skipped steps)
7.13 Solve 2 ๐ฅโ1 = 5.
3
Multiply by 3:
2 ๐ฅ โ 1 = 15
Add 1:
2 ๐ฅ = 16
Divide by 2:
๐ฅ = 8
Worked example (no skipped steps)
7.14 Solve ๐ฅ+4 = 7.
2
Multiply by 2:
๐ฅ + 4 = 14
Subtract 4:
๐ฅ = 10
Worked example (no skipped steps)
7.15 Solve 2 ๐ฅ + 5 = 2 ๐ฅ โ 1.
Subtract 2 ๐ฅ from both sides:
5 = โ1
This is false, so the equation has no solution.
Worked example (no skipped steps)
7.16 Solve 4( ๐ฅ + 1) = 4 ๐ฅ + 4.
Distribute:
4 ๐ฅ + 4 = 4 ๐ฅ + 4
Subtract 4 ๐ฅ:
4 = 4
This is always true, so the equation has infinitely many solutions.
Step-by-step solutions
Worked example (no skipped steps)
7.17 Solve 3( ๐ฅ โ 2) = 3 ๐ฅ + 5.
Distribute:
3 ๐ฅ โ 6 = 3 ๐ฅ + 5
Subtract 3 ๐ฅ:
โ6 = 5
This is false, so there is no solution.
Worked example (no skipped steps)
7.18 Solve 7 โ 2( ๐ฆ + 3) = 1.
Distribute:
7 โ 2 ๐ฆ โ 6 = 1
Combine:
1 โ 2 ๐ฆ = 1
Subtract 1:
โ2 ๐ฆ = 0
Divide by โ2:
๐ฆ = 0
Worked example (no skipped steps)
7.19 Solve 5( ๐ฅ โ 2) = 3 ๐ฅ + 6.
Distribute:
5 ๐ฅ โ 10 = 3 ๐ฅ + 6
Subtract 3 ๐ฅ:
2 ๐ฅ โ 10 = 6
Add 10:
2 ๐ฅ = 16
Divide by 2:
๐ฅ = 8
Worked example (no skipped steps)
7.20 Solve 3 ๐ฅ+6 = 8.
3
Multiply by 3:
3 ๐ฅ + 6 = 24
Subtract 6:
3 ๐ฅ = 18
Divide by 3:
๐ฅ = 6
165
Worked example (no skipped steps)
7.21 Solve 2(3 ๐ โ 1) + 5 = 15.
Distribute:
6 ๐ โ 2 + 5 = 15
Combine:
6 ๐ + 3 = 15
Subtract 3:
6 ๐ = 12
Divide by 6:
๐ = 2
Worked example (no skipped steps)
7.22 Solve 4 โ 3(2 ๐ฅ โ 1) = โ11.
Distribute:
4 โ 6 ๐ฅ + 3 = โ11
Combine:
7 โ 6 ๐ฅ = โ11
Subtract 7:
โ6 ๐ฅ = โ18
Divide by โ6:
๐ฅ = 3
Worked example (no skipped steps)
7.23 Decide whether 4 ๐ + 7 = 4 ๐ โ 2 has one solution, no solution, or infinitely many solutions.
Subtract 4 ๐ from both sides:
7 = โ2
This is false, so there is no solution.
Step-by-step solutions
Worked example (no skipped steps)
7.24 Decide whether 3( ๐ โ 2) = 3 ๐ โ 6 has one solution, no solution, or infinitely many solutions.
Distribute:
3 ๐ โ 6 = 3 ๐ โ 6
Subtract 3 ๐:
โ6 = โ6
This is always true, so there are infinitely many solutions.
