Algebra Foundations for Normal People by Gabriel Beguerie - HTML preview
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Chapter 5
Worked example (no skipped steps)
5.1 Simplify 5 ๐ฅ + 2 ๐ฅ.
5 ๐ฅ + 2 ๐ฅ = 7 ๐ฅ
Worked example (no skipped steps)
5.2 Simplify 7 ๐ โ 3 + 2 ๐ + 8.
Combine like terms:
7 ๐ + 2 ๐ = 9 ๐,
โ3 + 8 = 5
So:
9 ๐ + 5
Step-by-step solutions
Worked example (no skipped steps)
5.3 Expand 4( ๐ฅ + 3).
4 ๐ฅ + 12
Worked example (no skipped steps)
5.4 Expand โ3( ๐ฆ โ 2).
โ3 ๐ฆ + 6
Worked example (no skipped steps)
5.5 Expand and simplify 2(3 ๐ฅ + 1) โ 4.
2(3 ๐ฅ + 1) โ 4 = 6 ๐ฅ + 2 โ 4 = 6 ๐ฅ โ 2
Worked example (no skipped steps)
5.6 Expand and simplify โ2(4 ๐ฅ โ 5) + 3.
โ8 ๐ฅ + 10 + 3 = โ8 ๐ฅ + 13
Worked example (no skipped steps)
5.7 Decide whether 3 ๐ฅ and 3 are like terms.
No. One has a variable and one does not.
Worked example (no skipped steps)
5.8 Simplify 6 ๐ โ 2 ๐ + 9 โ 4.
6 ๐ โ 2 ๐ = 4 ๐,
9 โ 4 = 5
So the result is
4 ๐ + 5
Worked example (no skipped steps)
5.9 Simplify 4 ๐ฅ + 7 โ 2 ๐ฅ + 3.
Combine the like terms with ๐ฅ:
4 ๐ฅ โ 2 ๐ฅ = 2 ๐ฅ
Combine the constants:
7 + 3 = 10
So the expression becomes:
2 ๐ฅ + 10
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Answer: 2 ๐ฅ + 10.
Worked example (no skipped steps)
5.10 Expand 3( ๐ฅ โ 5).
Distribute the 3 to each term inside the parentheses:
3( ๐ฅ โ 5) = 3 ยท ๐ฅ + 3 ยท (โ5)
So:
3( ๐ฅ โ 5) = 3 ๐ฅ โ 15
Answer: 3 ๐ฅ โ 15.
Worked example (no skipped steps)
5.11 Simplify โ2(4 ๐ฆ โ 1) + 3 ๐ฆ.
Distribute โ2 first:
โ2(4 ๐ฆ โ 1) = โ8 ๐ฆ + 2
Now add the remaining 3 ๐ฆ:
โ8 ๐ฆ + 2 + 3 ๐ฆ
Combine the like terms:
โ8 ๐ฆ + 3 ๐ฆ = โ5 ๐ฆ
So the result is:
โ5 ๐ฆ + 2
Answer: โ5 ๐ฆ + 2.
Worked example (no skipped steps)
5.12 Evaluate 2 ๐ + 5 ๐ when ๐ = 3 and ๐ = โ1.
Substitute the values:
2 ๐ + 5 ๐ = 2(3) + 5(โ1)
Multiply:
2(3) = 6 ,
5(โ1) = โ5
Now add:
6 + (โ5) = 1
Answer: 1.
Step-by-step solutions
Worked example (no skipped steps)
5.13 Simplify 3 ๐ฅ + 5 โ 2 ๐ฅ + 7.
Combine like terms:
3 ๐ฅ โ 2 ๐ฅ = ๐ฅ
5 + 7 = 12
So:
๐ฅ + 12
Answer: ๐ฅ + 12.
Worked example (no skipped steps)
5.14 Distribute and simplify 4( ๐ฅ โ 3).
4( ๐ฅ โ 3) = 4 ๐ฅ โ 12
Answer: 4 ๐ฅ โ 12.
Worked example (no skipped steps)
5.15 Distribute and simplify โ2(5 ๐ฆ + 1).
โ2(5 ๐ฆ + 1) = โ10 ๐ฆ โ 2
Answer: โ10 ๐ฆ โ 2.
Worked example (no skipped steps)
5.16 Simplify 2(3 ๐ โ 4) + 5 ๐.
Distribute first:
2(3 ๐ โ 4) = 6 ๐ โ 8
Then combine like terms:
6 ๐ โ 8 + 5 ๐ = 11 ๐ โ 8
Answer: 11 ๐ โ 8.
Worked example (no skipped steps)
5.17 Simplify 7 โ (2 ๐ฅ โ 5).
Distribute the negative sign:
7 โ 2 ๐ฅ + 5
Combine constants:
12 โ 2 ๐ฅ
Answer: 12 โ 2 ๐ฅ.
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Worked example (no skipped steps)
5.18 Combine like terms: 6 ๐ โ 2 + 4 ๐ + 9.
6 ๐ + 4 ๐ = 10 ๐
โ2 + 9 = 7
Answer: 10 ๐ + 7.
Worked example (no skipped steps)
5.19 Simplify 3(2 ๐ + 5) โ 4( ๐ โ 1).
Distribute:
6 ๐ + 15 โ 4 ๐ + 4
Combine like terms:
2 ๐ + 19
Answer: 2 ๐ + 19.
Worked example (no skipped steps)
5.20 Simplify 5 โ 3( ๐ฅ โ 2).
Distribute the โ3:
5 โ 3 ๐ฅ + 6 = 11 โ 3 ๐ฅ
Answer: 11 โ 3 ๐ฅ.
