# Amusements in Mathematics HTML version

Of course a half-square rectangle is the same as a double square, or two equal squares
joined together. Therefore, if you want to solve the puzzle of cutting a Greek cross into
four pieces to form two separate squares of the same size, all you have to do is to
continue the short cut in Fig. 38 right across the cross, and you will have four pieces of
the same size and shape. Now divide Fig. 37 into two equal squares by a horizontal cut
midway and you will see the four pieces forming the two squares.
Cut a Greek cross into five pieces that will form two separate squares, one of which shall
contain half the area of one of the arms of the cross. In further illustration of what I have
already written, if the two squares of the same size A B C D and B C F E, in Fig. 41, are
cut in the manner indicated by the dotted lines, the four pieces will form the large square
A G E C. We thus see that the diagonal A C is the side of a square twice the size of A B
C D. It is also clear that half the diagonal of any square is equal to the side of a square of
half the area. Therefore, if the large square in the diagram is one of the arms of your
cross, the small square is the size of one of the squares required in the puzzle.
The solution is shown in Figs. 42 and 43. It will be seen that the small square is cut out
whole and the large square composed of the four pieces B, C, D, and E. After what I have
written, the reader will have no difficulty in seeing that the square A is half the size of
one of the arms of the cross, because the length of the diagonal of the former is clearly
the same as the side of the latter. The thing is now self-evident. I have thus tried to show
that some of these puzzles that many people are apt to regard as quite wonderful and
bewildering, are really not difficult if only we use a little thought and judgment. In
conclusion of this particular subject I will give four Greek cross puzzles, with detached
solutions.
142.—THE SILK PATCHWORK.