The Mathematics of P vs NP by hemant pandey - HTML preview

PLEASE NOTE: This is an HTML preview only and some elements such as links or page numbers may be incorrect.
Download the book in PDF, ePub, Kindle for a complete version.

 

 

 


800

801

802


selection of right points at each step is the basis of success of the method described. One last point about the tour being optimal, after each step we reject C(n,2) longer tours. In next step we again reject approximately C(n,2) tours. Note that the total tours rejected are C(n,2).C(n,2)


803


i.e. C(n, 2)


2 but total calculations are 2.C(n,2).Hence in n steps we reject C(n, 2) n (dont bother


804

805

806

807

 

 

808

 

 

809

 

 

810

 

 

811

 

 

812

 

 

813

 

814

815

816

817

818

819

820

821

822

823

824

825

826

827

828

829

830

831

832

833

834

835

836


many tours are common!) but total calculation are no more than n.C(n,2).Mathematically speaking with a check of polynomial origin we can effectively check tours of the range on non polynomial nature. The method succeeds only because it tries to transform multiplication involved in the formulation of solution (that is listing of all possible tours) to addition.